If the linear momentum measures 50 %then K. E will increase?

A. 50%
B. 125%
C. 100%
D. 25%

Submitted by: Ali

If the linear momentum measures 50 %then K. E will increase by 125%

Percentage increase in K.E,
(E)=[E2​−E1/E1​​​]×100=[E2/E1​​−1]×100
But Eαp²⇒E2/​E1​​=p²2​/p²1​​
∴ % increase in K.E. =[p²2​/p²1​​−1]×100
Let p1​=100, then
p2​=100+50=150% increase in
K.E.=[(150)²​/(100)²−1]×100=[225​/100−1]×100 =125%
Therefore, the percentage increase in its kinetic energy is 125%